A gas expands adiabatically at constant pressure such that its temperature T ∝ 1 V . The value of C p C v of gas is

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A gas expands adiabatically at constant pressure such that its temperature

T \propto \frac{1}{\sqrt{V}}

. The value of

\frac{C_{p}}{C_{v}}

of gas is

PhysicsThermodynamicsNEET

Options:

A $1.30$
B $1.50$
C $1.67$
D $2.00$

Solution:

2509 Upvotes Verified Answer

The correct answer is:

1.50

T \propto \frac{1}{\sqrt{V}}

T V^{\frac{1}{2}} =

constant

For adiabatic process,

T V^{γ - 1} =

const.

γ - 1 = \frac{1}{2}

∴ γ = \frac{3}{2} = 1.50

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