A gas expands adiabatically at constant pressure such that T ∝ 1 V The value of γ , i.e., C P C V of the gas will be

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A gas expands adiabatically at constant pressure such that

T \propto \frac{1}{\sqrt{V}}

The value of

γ

, i.e.,

(\frac{C_{P}}{C_{V}})

of the gas will be

ChemistryThermodynamics (C)JEE Main

Options:

A 1.30
B 1.50
C 1.70
D 2

Solution:

1532 Upvotes Verified Answer

The correct answer is: 1.50

T \propto \frac{1}{\sqrt{V}}

T V^{\frac{1}{2}} =

constant

For adiabatic process,

T V^{\frac{1}{2}} = T V^{γ - 1} =

constant

So

γ - 1 = \frac{1}{2}

γ = \frac{3}{2}

.

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