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A gas is allowed to expand against a constant external pressure of 2.5 bar from an initial volume of $2.5 \mathrm{~L}$ to a final volume of $4.5 \mathrm{~L}$. What is amount of work done?
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The correct answer is:
-500 J
$\begin{aligned} W & =-P\left(V_2-V_1\right) \\ & =-2.5(4.5-2.5) \\ & =-5.0 \mathrm{bar}-\mathrm{L} \\ & =-500 \mathrm{~J}\end{aligned}$
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