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Question: Answered & Verified by Expert
A gas mixture contains \(\mathrm{O}_2\) and \(\mathrm{N}_2\) in the ratio of \(1: 4\) by weight. The ratio of their number of molecules is
ChemistryStates of MatterJIPMERJIPMER 2008
Options:
  • A \(1: 8\)
  • B \(1: 4\)
  • C \(3: 16\)
  • D \(7: 32\)
Solution:
1817 Upvotes Verified Answer
The correct answer is: \(7: 32\)
\(\because\) The ratio of \(\mathrm{O}_2\) and \(\mathrm{N}_2\) by weight is \(1: 4\).
\(\therefore\) the ratio of \(\mathrm{O}_2\) and \(\mathrm{N}_2\) by moles \(=\frac{1}{32}: \frac{4}{28}\)
\(=7: 32\)

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