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A geostationary satellite orbits the earth at a height of nearly $36,000 \mathrm{~km}$ from the surface of the earth. What is the potential due to earth's gravity at the site of this satellite? (Consider the P.E. at infinity to be zero.) Mass of the earth $=6 \times 10^{24} \mathrm{~kg}$ Radius $=6400 \mathrm{~km}$
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Gravitational potential at a height $h$ above the surface of the earth $=V=\frac{-G M}{R+h}$ $=\frac{-6.67 \times 10^{-11} \times 6 \times 10^{24}}{\left(6.4 \times 10^6+36 \times 10^6\right)}=-9.4 \times 10^6 \mathrm{~J} / \mathrm{kg}$.
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