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Question: Answered & Verified by Expert
A healthy person eats the following diet$5 \mathrm{gm}$ raw sugar, $4 \mathrm{gm}$ albumin, $10 \mathrm{gm}$ pure buffalo ghee adultrated with $2 \mathrm{gm}$ vegetable ghee (hydrogenated vegetable oil) and $5 \mathrm{gm}$ lignin. How many calories he is likely to get?
BiologyBiomolecules (B)NEETNEET 2013 (Karnataka)
Options:
  • A 126
  • B 164
  • C 112
  • D 144
Solution:
1843 Upvotes Verified Answer
The correct answer is: 144


For carbohydrates, calorific value $=$ 4
Thus,
Raw sugar (carbohydrate) produce $=5 \times 4=20 \mathrm{kcal}$
Albumin (protcin) produce $=4 \times 4$ $=16 \mathrm{kcal}$
Ghee and vegetable oil (fat) $=9 \times$ $(10+2)=108 \mathrm{kcal}$
Total calories yield $=20+16+108$ $=144 \mathrm{kcal}$

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