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A heavy mass is attached at one end of a thin wire and whirled in a vertical circle. The chances of breaking the wire are maximum when
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The correct answer is:
the mass is at the lowest point of the circle.
When the mass is at the lowest point.
Explanation $\Rightarrow$ The Force acting on the Particles will be maximum in case of the Vertical circle when the Force acting will be in the direction of its tension force of string.
When this situation arises then,
Tension $(\mathrm{T})=\frac{\mathrm{mv}^{2}}{\mathrm{r}}$
$\therefore$ Force will be maximum at this position and there will likely be more chances to break.
This case will be there when the mass is at the lowest position.
$\therefore$ Option (b). is correct.
Explanation $\Rightarrow$ The Force acting on the Particles will be maximum in case of the Vertical circle when the Force acting will be in the direction of its tension force of string.
When this situation arises then,
Tension $(\mathrm{T})=\frac{\mathrm{mv}^{2}}{\mathrm{r}}$
$\therefore$ Force will be maximum at this position and there will likely be more chances to break.
This case will be there when the mass is at the lowest position.
$\therefore$ Option (b). is correct.
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