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Question: Answered & Verified by Expert
A hollow metal sphere of radius $R$ is charged with a charge $Q .$ The electric potential and intensity inside the sphere are respectively
PhysicsElectrostaticsWBJEEWBJEE 2016
Options:
  • A $\frac{Q}{4 \pi \varepsilon_{0} R^{2}}$ and $\frac{Q}{4 \pi \varepsilon_{0} R}$
  • B $\frac{Q}{4 \pi \varepsilon_{0} R}$ and zero
  • C zero and zero
  • D $\frac{4 \pi \varepsilon_{0} Q}{R}$ and $\frac{Q}{4 \pi \varepsilon_{0} R^{2}}$
Solution:
2465 Upvotes Verified Answer
The correct answer is: $\frac{Q}{4 \pi \varepsilon_{0} R}$ and zero
Inside a hollow charged sphere, the electric field intensity is always zero.
$\therefore$ $E=0$ but potential is constant.

Potential on the surtace of the hollow sphere
$$
V=\frac{K Q}{R}=\frac{1}{4 \pi \varepsilon_{0}} \cdot \frac{Q}{R}=\frac{Q}{4 \pi \varepsilon_{0} R}
$$
This is the potential $(\mathrm{V})$ inside the charged hollow meta sphere.

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