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Question: Answered & Verified by Expert
A horizontal disk is rotating with angular velocity ω about a vertical axis passing through its centre. A ball is placed at the centre of groove and pushed slightly. The velocity of the ball when it comes out of the groove-

PhysicsLaws of MotionJEE Main
Options:
  • A 32ωR
  • B ωR2
  • C ωR
  • D ωR2
Solution:
2565 Upvotes Verified Answer
The correct answer is: 32ωR

Let us consider the motion of the ball with respect to disk





Net force along groove=mω2r sinθ

=mω2r xr

=mω2x

 ma=mω2x

 v dvdx=ω2x

0vvdv=0R2ω2xdx

v22=ω22R22

 v=ωR2

vBall,Ground=vBall,Disk+ vDisk,Ground

 vBall,Ground

= ωR2+ωR22+2ωRωR2cos120°12

=32ωR

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