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A horizontal ray of light is incident on the right-angled prism with prism angle $6^{\circ}$. If the refractive index of the material of the prism is 1.5 , then the angle of emergence will be
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$9^{\circ}$
Deviation produced by a thin prism
$\delta=(\mu-1) A=\left(\frac{3}{2}-1\right) 6^{\circ}=3^{\circ}$
$\begin{aligned} \text { Angle of emergence }=e & =6^{\circ}+3^{\circ} \\ & =9^{\circ}\end{aligned}$
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