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Question: Answered & Verified by Expert
A is an optically inactive alkyl chloride which on reaction with aqueous $\mathrm{KOH}$ gives $\mathrm{B}$. $\mathrm{B}$ on heating with $\mathrm{Cu}$ at $300^{\circ} \mathrm{C}$ gives an alkene $\mathrm{C}$, what are $\mathrm{A}$ and $\mathrm{C}$
ChemistryHydrocarbonsJEE Main
Options:
  • A $\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{Cl}, \mathrm{CH}_{2}=\mathrm{CH}_{2}$
  • B $\mathrm{Me}_{3} \mathrm{CCl}, \mathrm{MeCH}=\mathrm{CH} \cdot \mathrm{Me}$
  • C $\mathrm{Me}_{3} \mathrm{CCl}, \mathrm{Me}_{2} \mathrm{C}=\mathrm{CH}_{2}$
  • D $\mathrm{Me}_{2} \mathrm{CH} . \mathrm{CH}_{2} \mathrm{Cl} \mathrm{Me}_{2} \mathrm{C}=\mathrm{CH}_{2}$
Solution:
1473 Upvotes Verified Answer
The correct answer is: $\mathrm{Me}_{3} \mathrm{CCl}, \mathrm{Me}_{2} \mathrm{C}=\mathrm{CH}_{2}$




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