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A linear object of height \( 10 \mathrm{~cm} \) is kept in front of a concave mirror of radius of curvature \( 15 \mathrm{~cm} \),
at a distance of \( 10 \mathrm{~cm} \). The image formed is
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at a distance of \( 10 \mathrm{~cm} \). The image formed is
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The correct answer is:
magnified and inverted
Given, height of object \( =10 \mathrm{~cm} \); radius of curvature \( =15 \mathrm{~cm} \); distance of object \( =10 \mathrm{~cm} \).
Since radius of curvature is \( 15 \mathrm{~cm} \), so focal length \( =\frac{15}{2}=7.5 \mathrm{~cm} \)
\( \Rightarrow f < u \)
Thus, the object is placed between centre of curvature and focus of the concave mirror.
Therefore, the image formed is magnified and inverted.
Since radius of curvature is \( 15 \mathrm{~cm} \), so focal length \( =\frac{15}{2}=7.5 \mathrm{~cm} \)
\( \Rightarrow f < u \)
Thus, the object is placed between centre of curvature and focus of the concave mirror.
Therefore, the image formed is magnified and inverted.
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