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A lot of 4 white and 4 red balls is randomly divided into two halves. What is the probability that there will be 2 red and 2 white balls in each half?
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The correct answer is:
$18 / 35$
Required probability $=\frac{{ }^{4} C_{2} \times{ }^{4} C_{2}}{{ }^{8} C_{2}}=\frac{36}{70}=\frac{18}{35}$
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