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A magnetic field is applied on an electron moving with a velocity of $10^7 \mathrm{~ms}^{-1}$ at an angle of $30^{\circ}$. Then the time period of revolution of the electron in a circular path of radius $2 \mathrm{~m}$ is ____
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The correct answer is:
$2.5 \times 10^{-6} \mathrm{~s}$
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