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A man makes attempts to hit the target. The probability of hitting the target is $\frac{3}{5}$. Then the probability that $A$ hit the target exactly 2 times in 5 attempts, is
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Verified Answer
The correct answer is:
$\frac{144}{625}$
Probability of success
$(p)=\frac{3}{5} \Rightarrow q=1-p=\frac{2}{5}$
Hence the probability of 2 hits in 5 attempts
$={ }^5 C_2\left(\frac{3}{5}\right)^2\left(\frac{2}{5}\right)^3=\frac{144}{625}$.
$(p)=\frac{3}{5} \Rightarrow q=1-p=\frac{2}{5}$
Hence the probability of 2 hits in 5 attempts
$={ }^5 C_2\left(\frac{3}{5}\right)^2\left(\frac{2}{5}\right)^3=\frac{144}{625}$.
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