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A man saves Rs. 200 in each of the first three months of his service. In each of the subsequent months his saving increases by Rs. 40 more than the saving of immediately previous month. His total saving from the start of service will be Rs. 11040 after
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The correct answer is:
21 months
21 months
$\begin{array}{ccccccc}1 & 2 & 3 & 4 & 5 & 6 & \ldots \ldots . \\ 200 & 200 & 200 & 240 & 280 & \ldots \ldots . & \ldots \ldots \ldots\end{array}$
Sum $=11040$
$120+80+160+40+200+240+\ldots=11040$
$\frac{n}{2}[2 a+(n-1) d]+80+40=11040$
$\frac{n}{2}[240+(n-1) 40]=10920$
$n[6+n-1]=546$
$n(n+5)=546$
$n=21$
Sum $=11040$
$120+80+160+40+200+240+\ldots=11040$
$\frac{n}{2}[2 a+(n-1) d]+80+40=11040$
$\frac{n}{2}[240+(n-1) 40]=10920$
$n[6+n-1]=546$
$n(n+5)=546$
$n=21$
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