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A man wants to reach a certain destination. One-sixth of the total distance is muddy while half the distance is tar road. For the remaining distance he takes a boat. His speed of traveling in mud, in water, on tar road is in the ratio $3: 4: 5$. The ratio of the durations he requires to cross the patch of mud, stream and tar road is
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$10: 15: 18$
Let distance is $6 \mathrm{x}$
$\begin{array}{llll} & \text { mud }: & \text { tar } & \text { : } & \text { stream } \\ \text { distance } & x & : & 3 x & : & 2 x \\ \text { speed } & 3 v & : & 5 v & : & 4 v \\ \text { time } & \frac{x}{3 v} & : & \frac{3 x}{5 v} & : & \frac{2 x}{4 v} \\ & 10 & : & 18 & : & 15 & \end{array}$
$\begin{array}{llll} & \text { mud }: & \text { tar } & \text { : } & \text { stream } \\ \text { distance } & x & : & 3 x & : & 2 x \\ \text { speed } & 3 v & : & 5 v & : & 4 v \\ \text { time } & \frac{x}{3 v} & : & \frac{3 x}{5 v} & : & \frac{2 x}{4 v} \\ & 10 & : & 18 & : & 15 & \end{array}$
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