A massless square loop, of wire of resistance 10 Ω , supporting a mass of 1 g , hangs vertically with one of its sides in a uniform magnetic field of 10 3 G , directed outwards in the shaded region. A dc voltage V is applied to the loop. For what value of V , the magnetic force will exactly balance the weight of the supporting mass of 1 g ? (If sides of the loop = 10 cm , g = 10 m s - 2 ) .

Question

A massless square loop, of wire of resistance 10 Ω , supporting a mass of 1 g , hangs vertically with one of its sides in a uniform magnetic field of 10 3 G , directed outwards in the shaded region. A dc voltage V is applied to the loop. For what value of V , the magnetic force will exactly balance the weight of the supporting mass of 1 g ? (If sides of the loop = 10 cm , g = 10 m s - 2 ) ., 1 10 V, 100 V, 1 V, 10 V

MARKS App · Accepted Answer

For balancing of force, Magnetic force F m = weight of supporting mass m g . ∴ I L B = m g ∴ V R L B = m g ∵ From Ohm's law , I = V R ∴ V = m g R L B = 1 × 10 - 3 kg 10 m s - 2 10 Ω 0 . 1 m 10 3 × 10 - 4 T = 10 V

Search any question & find its solution

Looking for more such questions to practice?