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A metal has bcc structure and the edge length of its unit cell is $3.04 Å$. The volume of the unit cell in $\mathrm{cm}^{3}$ will be,
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Verified Answer
The correct answer is:
$2.81 \times 10^{-23} \mathrm{~cm}^{3}$
Volume of unit cell $(\mathrm{V})=\mathrm{a}^{3}$
$\begin{array}{l}
\therefore \quad=\left(3.04 \times 10^{-8} \mathrm{~cm}\right)^{3} \\
=\quad 2.81 \times 10^{-23} \mathrm{~cm}^{3}
\end{array}$
$\begin{array}{l}
\therefore \quad=\left(3.04 \times 10^{-8} \mathrm{~cm}\right)^{3} \\
=\quad 2.81 \times 10^{-23} \mathrm{~cm}^{3}
\end{array}$
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