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Question: Answered & Verified by Expert
A metal oxide has the formula Z2O3 . It can be reduced by hydrogen to give free metal and water. 0.1596 g of the metal oxide requires 6 mg of hydrogen for complete reduction. The atomic weight of the metal is
ChemistryRedox ReactionsJEE Main
Options:
  • A 27.9
  • B 159.6
  • C 79.8
  • D 55.8
Solution:
1903 Upvotes Verified Answer
The correct answer is: 55.8
Z2O3+3H22Z+3H2O

Valency of metal in Z2O3=3

0.1596 g of Z 2 O 3 react with 6 mg of H 2

So 1 g of H2 react with =0.15960.006=26.6 g of Z2O3

So Eq. wt. of Z2O3=26.6

Now, Eq. wt. of Z+ Eq. wt. of O= Eq. wt. of Z+8=26.6

So Eq. wt. of Z=26.6-8=18.6

So At. wt. of Z=18.6×3=55.8

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