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A metre scale is supported on a wedge at its centre of gravity. A body of weight ' $\mathrm{w}$ ' is suspended from the $20 \mathrm{~cm}$ mark and another weight of 25 gram is suspended from $74 \mathrm{~cm}$ mark balance it and the metre scale remains perfectly horizontal. Neglecting the weight of the metre scale, the weight of the body is
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The correct answer is:
20 gram-wt
Taking moments about the centre of the scale we get
$$
\begin{aligned}
& \mathrm{W} \times 30=25 \times 24 \\
& \therefore \mathrm{W}=\frac{25 \times 24}{30}=20 \mathrm{~g}-\mathrm{wt}
\end{aligned}
$$
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