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A mixture of benzaldehyde and formaldehyde on heating with aqueous $\mathrm{NaOH}$ solution gives
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benzyl alcohol and sodium formate
Benzaldyde and formaldehyde, both do not have $\alpha$ - hydrogen atom, so both will undergo Cannizzaro reaction; here formaldehyde will always be oxidised to formate while the other aldehyde $\left(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{CHO}\right.$ or any other aldehyde not having $\alpha-\mathrm{H}$, viz- $\left.\mathrm{Me}_{3} \mathrm{CCHO}\right)$ will always be reduced to corresponding alcohol (crossed Cannizzaro reaction)
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