A nucleus with mass number 240 breaks into two fragments each of mass number 120 , the binding energy per nucleon of unfragmented nuclei is 7 . 6 MeV while that of fragments is 8 . 5 MeV . The total gain in the binding energy in the process is :

Question

A nucleus with mass number 240 breaks into two fragments each of mass number 120 , the binding energy per nucleon of unfragmented nuclei is 7 . 6 MeV while that of fragments is 8 . 5 MeV . The total gain in the binding energy in the process is :, 0 . 9 MeV, 9 . 4 MeV, 216 MeV, 804 MeV

MARKS App · Accepted Answer

Given binding energy per nucleon of X , Y & Z are, 7 . 6 M eV , 8 . 5 M eV & 8 . 5 M eV respectively. ⇒ B . E . = ( 120 × 8 . 5 ) + ( 120 × 8 . 5 ) - 240 × 7 . 6 ⇒ B . E . = 2040 - 1824 = 216 M eV

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