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Question: Answered & Verified by Expert
A parallel plate capacitor of capacitance C is connected to a battery and is charged to a potential difference V. Another capacitor of capacitance 2C is similarly charged to a potential difference 2V. The charging battery is now disconnected and the capacitors are connected in parallel to each other in such a way that the positive terminal of one is connected to the negative terminal of the other. The final energy of the configuration is
PhysicsElectrostaticsNEET
Options:
  • A zero
  • B 256CV2
  • C 92CV2
  • D 32CV2
Solution:
2080 Upvotes Verified Answer
The correct answer is: 32CV2
The diagramatic representation of given problem is shown in the figure.


The net charge shared between the two capacitors is,

         Q'=Q2-Q1=4CV-CV=3CV 

The two capacitors will have the same potential, say V'.
The net capacitance of the parallel combination of the two capacitors will be,

          C'=C1+C2=C+2C=3C

The potential difference across the capacitors will be,

          V'=Q'C'=3CV3C=V    

The electrostatic energy of the capacitors will be,

        U'=12C'V'2=123CV2=32CV2
 

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