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A parents has two children. If one of them is boy, then the probability that other is, also a boy, is
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The correct answer is:
$1 / 3$
Total cases are $B B, B G, G B, G G=4$ Favourable cases are $B B, B G, G B=3$ Let $P(A)=$ Probability of a boy in two children
$$
=\frac{3}{4}
$$
The probability that the second child is also a boy is $P(A \cap B)=\frac{1}{4}$
We have to find $P(B / A)=\frac{P(A \cap B)}{P(A)}=\frac{1 / 4}{3 / 4}=\frac{1}{3}$
$$
=\frac{3}{4}
$$
The probability that the second child is also a boy is $P(A \cap B)=\frac{1}{4}$
We have to find $P(B / A)=\frac{P(A \cap B)}{P(A)}=\frac{1 / 4}{3 / 4}=\frac{1}{3}$
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