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A particle at a distance of $1 \mathrm{~m}$ from the origin starts moving such that $\mathrm{dr} / \mathrm{d} \theta=\mathrm{r}$, where $(\mathrm{r}, \theta)$ are polar coordinates. Then the angle between resultant velocity and tangential velocity component is
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45 degrees
$\overrightarrow{\mathrm{AB}}=$ Direction of resultant velocity $\overrightarrow{\mathrm{AD}}=$ Direction of tangential velocity
$\begin{array}{c}
\forall \tan \alpha=\frac{\mathrm{dr}}{\operatorname{rd} \theta}=\frac{\mathrm{r}}{\mathrm{r}} \\
\tan \alpha=1 \\
\alpha=45^{\circ}
\end{array}$
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