A particle leaves the origin with initial velocity v → = 3 i ^ m s - 1 and a constant acceleration a → = - 1 i ^ - 0 . 5 j ^ m s - 2 . The position vector of particle, when it reaches its maximum x -coordinate, is

Question

A particle leaves the origin with initial velocity v → = 3 i ^ m s - 1 and a constant acceleration a → = - 1 i ^ - 0 . 5 j ^ m s - 2 . The position vector of particle, when it reaches its maximum x -coordinate, is, 9 2 i ^ - j ^ m, 9 2 i ^ - j ^ 2 m, 9 2 - i ^ + j ^ m, 9 2 i ^ 2 - j ^ m

MARKS App · Accepted Answer

Using the first equation of motion, v = u + a t , in-plane, v → t = 3 - 1 × t i ^ + 0 - 0 . 5 t j ^ . . . i for maximum positive, x coordinate when v x become zero. ∴ 3 - t = 0 ⇒ t = 3 s than r → 3 = 4 . 5 i ^ - 2 . 25 j ^ = 9 2 i ^ - j ^ 2 m

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