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A particle of charge $-16 \times 10^{-18}$ coulomb moving with velocity $10 \mathrm{~ms}^{-1}$ along the $\mathrm{x}$-axis enters a region where a magnetic field of induction $\mathrm{B}$ is along the $\mathrm{y}$-axis, and an electric field of magnitude $10^4 \mathrm{~V} / \mathrm{m}$ is along the negative z-axis. If the charged particle continues moving along the $\mathrm{x}$-axis, the magnitude of $\mathrm{B}$ is
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$10^3 \mathrm{~Wb} / \mathrm{m}^2$
$10^3 \mathrm{~Wb} / \mathrm{m}^2$
Since there is no deviation in the path of the charged particle, so net force due to presence of electric and magnetic field must be zero $\Rightarrow \mathrm{vB}=\mathrm{qE} \Rightarrow \mathrm{B}=\frac{\mathrm{E}}{\mathrm{V}}=\frac{10^4}{10}=10^3 \mathrm{~Wb} / \mathrm{m}^2$
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