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A particle of charge $e$ and mass $m$ moves with a velocity $v$ in a magnetic field $B$ applied perpendicular to the motion of the particle. The radius $r$ of its path in the field is
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Verified Answer
The correct answer is:
$\frac{m v}{B e}$
Radius of path, $\quad r-\frac{m v}{q B}$
Here,
$q=e$
So,
$r=\frac{m v}{e B}$
Here,
$q=e$
So,
$r=\frac{m v}{e B}$
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