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A particle of mass $100 \mathrm{~g}$ is thrown vertically upwards with a speed of $5 \mathrm{~m} / \mathrm{s}$. the work done by the force of gravity during the time the particle goes up is
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The correct answer is:
$-1.25 \mathrm{~J}$
$-1.25 \mathrm{~J}$
$-m g h=-m g\left(\frac{v^2}{2 g}\right)=-1.25 \mathrm{~J}$
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