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Question: Answered & Verified by Expert
A particle starts executing simple harmonic motion (SHM) of amplitude a and total energy E. At any instant, its kinetic energy is 3E4, then its displacement y is given by:
PhysicsOscillationsJEE MainJEE Main 2021 (27 Jul Shift 1)
Options:
  • A y=a
  • B y=a2
  • C y=a32
  • D y=a2
Solution:
1814 Upvotes Verified Answer
The correct answer is: y=a2
E=12Ka2
3E4=12 Ka2-y2v
34×12Ka2=12 Ka2-y2
y2=a2-3a24
y=a2

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