A person sitting in the ground floor of a building notices through the window, of height 1 . 5 m , a ball dropped from the roof of the building crosses the window in 0 . 1 s . What is the velocity of the ball when it is at the topmost point of the window? g = 10 m s - 2

Question

A person sitting in the ground floor of a building notices through the window, of height 1 . 5 m , a ball dropped from the roof of the building crosses the window in 0 . 1 s . What is the velocity of the ball when it is at the topmost point of the window? g = 10 m s - 2, 15 . 5 m s - 1, 14 . 5 m s - 1, 4 . 5 m s - 1, 20 m s - 1

MARKS App · Accepted Answer

First, recall the second equation of motion of kinematics, in terms of initial speed, time, and uniform acceleration, s = u t + 1 2 a t 2 . Now make a diagram related to motion of the particle, then put the values in second equation of motion, ⇒ 1 . 5 = u ( 0 . 1 ) + 1 2 ( 10 ) ( 0 . 1 ) ( 0 . 1 ) ⇒ 15 = u + 0 . 5 ⇒ u = 14 . 5 m s - 1 .

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