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A plano convex lens of material of refractive index $\mu_1$ exactly fits into a plano concave lens of material of refractive index $\mu_2$. If $R$ is the radius of curvature of the curved surfaces of the lenses and the plane surfaces of the lenses are parallel, the focal length of the combination is
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The correct answer is:
$\begin{aligned} & \frac{\mathrm{R}}{\mu_1-\mu_2}\end{aligned}$
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