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A positive charge $Q$ is situated at the centre of a cube. The electric flux through any face of the cube is (in SI units)
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The correct answer is:
$\frac{Q}{6 \varepsilon_{0}}$
The positive charge $Q$ is situated at the centre of a cube
According to Gauss theorem, the flux from any closed surface
$$
\phi_{E}=\frac{Q}{\varepsilon_{0}}
$$
Cube has 6 faces, so electric flux from any face $\phi_{z}=\frac{Q}{6 \varepsilon_{0}}$
According to Gauss theorem, the flux from any closed surface
$$
\phi_{E}=\frac{Q}{\varepsilon_{0}}
$$
Cube has 6 faces, so electric flux from any face $\phi_{z}=\frac{Q}{6 \varepsilon_{0}}$
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