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A projectile A is thrown at an angle of $30^{\circ}$ to the horizontal from point P. At the same time, another projectile $\mathrm{B}$ is thrown with velocity $\mathrm{v}_{2}$ upwards from the point $Q$ vertically below the highest point. For $\mathrm{B}$ to collide with $\mathrm{A}, \frac{\mathrm{v}_{2}}{\mathrm{v}_{1}}$ should be
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The correct answer is:
$\frac{1}{2}$
This happen when vertical velocity of both are same.
$\therefore v_{2}=v_{1} \sin 30^{\circ} \text { or } \frac{v_{2}}{v_{1}}=\frac{1}{2}$
$\therefore v_{2}=v_{1} \sin 30^{\circ} \text { or } \frac{v_{2}}{v_{1}}=\frac{1}{2}$
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