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Question: Answered & Verified by Expert
A proton is about 1840 times heavier than an electron. When it is accelerated by a potential difference of $1 \mathrm{kV}$, its kinetic energy will be
PhysicsDual Nature of MatterAIIMSAIIMS 2003
Options:
  • A $1840 \mathrm{keV}$
  • B $1 / 1840 \mathrm{keV}$
  • C $1 \mathrm{keV}$
  • D $920 \mathrm{keV}$.
Solution:
1754 Upvotes Verified Answer
The correct answer is: $1 \mathrm{keV}$
The charge on a proton is equal to $e$, the electronic charge. The potential difference is $V=1 \mathrm{kV}$. Hence the kinetic energy of the proton is $E=1 \mathrm{keV}$.

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