A ray of light passes from a medium $ A $ having refractive index $ 1.6 $ to the medium $ B $ having refractive index $ 1.5 $. The value of critical angle of medium $ A $ is

Question

A ray of light passes from a medium $ A $ having refractive index $ 1.6 $ to the medium $ B $ having refractive index $ 1.5 $. The value of critical angle of medium $ A $ is, $ \sin ^{-1}\left(\frac{16}{15}\right) $, $ \sin ^{-1} \sqrt{\frac{16}{15}} $, $ \sin ^{-1}\left(\frac{1}{2}\right) $, $ \sin ^{-1}\left(\frac{15}{16}\right) $

MARKS App · Accepted Answer

As the law of refraction we have, sin i c sin 90 = 1 . 5 1 . 6 , where i c is the critical angle. sin i c = 15 16 i c = sin - 1 15 16

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