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A reaction having equal energies of activation for forward and reverse reactions has
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The correct answer is:
$\Delta H=0$
Energy profile diagram for a reaction is as From the figure, it is clear that
So, \(\left(E_2\right)_b=\left(E_2\right)_f+\Delta H\left(\right.\) as, \(\left(E_2\right)_b=\left(E_2\right)_f\)
So, \(\Delta H=0\).
[Here $\left(E_2\right)_b=$ activation energy of backward reaction and $\left(E_2\right)_f=$ activation energy of forward reaction].
So, \(\left(E_2\right)_b=\left(E_2\right)_f+\Delta H\left(\right.\) as, \(\left(E_2\right)_b=\left(E_2\right)_f\)
So, \(\Delta H=0\).
[Here $\left(E_2\right)_b=$ activation energy of backward reaction and $\left(E_2\right)_f=$ activation energy of forward reaction].
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