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A resistor $R$, an inductor $L$ and a capacitor $C$ are connected in series to an oscillator of frequency $N$. If the resonance frequency is $N_R$, then the current lags behind voltage, when
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The correct answer is:
$N>N_R$
Current lags behind the voltage,
$\begin{aligned}
& X_L>X_C \\
& \Rightarrow \omega L>\frac{1}{\omega C} \\
& \Rightarrow \omega>\frac{1}{\sqrt{L C}} \\
& \Rightarrow N>N_R
\end{aligned}$
$\begin{aligned}
& X_L>X_C \\
& \Rightarrow \omega L>\frac{1}{\omega C} \\
& \Rightarrow \omega>\frac{1}{\sqrt{L C}} \\
& \Rightarrow N>N_R
\end{aligned}$
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