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A resistor $\mathrm{R}$, an inductor $\mathrm{L}$ and capacitor $\mathrm{C}$ are connected in series to an oscillator of frequency n. If the resonant frequency is $n_{r}$, then the current lags behind voltage, when
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The correct answer is:
$n>n_{\mathrm{r}}$
When reactance of inductance is mroe than the reactance of cndenser, the current will lag behind the voltage.
Thus $\omega L < \frac{1}{\omega c}$ or $\omega>\frac{1}{\sqrt{L C}}$
or $\mathrm{n}>\frac{1}{2 \pi \sqrt{\mathrm{LC}}}$ or $\mathrm{n}>\mathrm{n}_{\mathrm{r}}$
$\mathrm{n}_{\mathrm{T}}=$ resonant frequency
Thus $\omega L < \frac{1}{\omega c}$ or $\omega>\frac{1}{\sqrt{L C}}$
or $\mathrm{n}>\frac{1}{2 \pi \sqrt{\mathrm{LC}}}$ or $\mathrm{n}>\mathrm{n}_{\mathrm{r}}$
$\mathrm{n}_{\mathrm{T}}=$ resonant frequency
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