Search any question & find its solution
Question:
Answered & Verified by Expert
A rod of length $20 \mathrm{~cm}$ is rotating with angular speed of $100 \mathrm{rps}$ in a magnetic field of strength $0.5 T$ about it's one end. What is the potential difference between two ends of the rod
Options:
Solution:
1499 Upvotes
Verified Answer
The correct answer is:
$6.28 \mathrm{~V}$
$e=\left.\frac{1}{2} B\right|^2 \omega=B I^2 \pi v$
$\Rightarrow e=0.5\left(20 \times 10^{-2}\right)^2 \times 3.14 \times 100=6.28 \mathrm{~V}$
$\Rightarrow e=0.5\left(20 \times 10^{-2}\right)^2 \times 3.14 \times 100=6.28 \mathrm{~V}$
Looking for more such questions to practice?
Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.