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Question: Answered & Verified by Expert
A rod of weight W is supported by two parallel knife edges A and B and is in equilibrium in a horizontal position. The knives are at a distance d from each other. The centre of mass of the rod is at distance x from A . the normal reaction on A is:
PhysicsLaws of MotionNEETNEET 2015 (Phase 1)
Options:
  • A Wxd
  • B Wdx
  • C Wd-xx
  • D Wd-xd
Solution:
1256 Upvotes Verified Answer
The correct answer is: Wd-xd

Equation for force balance
NA+NB=W ...(i)
NB=W-NA
Equation for torque balance about centre of mass of rod.
NAx=NBd-x
NAx=W-NAd-x
NAx=Wd-Wx-NAd+NAx
NAd=Wd-x
NA=Wd-xd

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