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A sample of calcium carbonate $\left(\mathrm{CaCO}_3\right)$ has the following percentage composition : $\mathrm{Ca}=40 \% ; \mathrm{C}=$ $12 \% ; O=48 \%$
If the law of constant proportions is true, then the weight of calcium in $4 g$ of a sample of calcium carbonate obtained from another source will be
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If the law of constant proportions is true, then the weight of calcium in $4 g$ of a sample of calcium carbonate obtained from another source will be
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The correct answer is:
$1.6 \mathrm{~g}$
In $100 \mathrm{~g} \mathrm{CaCO3,} 40 \mathrm{~g}$ Ca is present.
In 4 g CaCO3, Let x g Ca be present
$\begin{aligned} & x / 4=40 / 100 \\ & \Rightarrow x=1.6 \mathrm{~g}\end{aligned}$
In 4 g CaCO3, Let x g Ca be present
$\begin{aligned} & x / 4=40 / 100 \\ & \Rightarrow x=1.6 \mathrm{~g}\end{aligned}$
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