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Question: Answered & Verified by Expert
A sample of drinking water was found to be severely contaminated with chloroform ( \(\mathrm{CHCl}_3\) ), supposed to be a carcinogen. The level of contamination was \(15 \mathrm{ppm}\) (by mass).
(i) express this in percent by mass.
(ii) determine the molality of chloroform in the water sample.
ChemistrySolutions
Solution:
1587 Upvotes Verified Answer
\(15 \mathrm{ppm}\) means 15 parts in million \(\left(10^6\right)\) by mass in the solution.
\(\therefore\) Percentage by mass \(=\frac{15}{10^6} \times 100=15 \times 10^{-4} \%\)
As only \(15 \mathrm{~g}\) of chloroform is present in \(10^6 \mathrm{~g}\) of the solution, mass of the solvent \(=10^6 \mathrm{~g}\)
Molar mass of \(\mathrm{CHCl}_3=12+1+3 \times 35 \cdot 5\)
\(=119 \cdot 5 \mathrm{~g} \mathrm{~mol}^{-1}\)
Moles of \(\mathrm{CHCl}_3=\frac{15}{119 \cdot 5}\)
\(\therefore\) Molality \(=\frac{15 / 119.5 \times 1000}{10^6}=1.25 \times 10^{-4} \mathrm{~m}\)

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