Search any question & find its solution
Question:
Answered & Verified by Expert
A satellite $S_1$ of mass $m$ is moving in an orbit of radius $r$. Another satellite $S_2$ of mass $2 \mathrm{~m}$ is moving in an orbit of radius $2 r$. The ratio of time period of satellite $S_2$ to that of $S_1$ is
Options:
Solution:
2327 Upvotes
Verified Answer
The correct answer is:
$2 \sqrt{2}: 1$
According to Kepler's Law of periods:
$T^2 \propto R^3$
Therefore,
$\frac{T_2}{T_1}=\left(\frac{2 r}{r}\right)^{\frac{3}{2}}=\frac{2 \sqrt{2}}{1}$
$T^2 \propto R^3$
Therefore,
$\frac{T_2}{T_1}=\left(\frac{2 r}{r}\right)^{\frac{3}{2}}=\frac{2 \sqrt{2}}{1}$
Looking for more such questions to practice?
Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.