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Question: Answered & Verified by Expert
A series LCR circuit of R=5 Ω, L=20 mH and C=0.5 μF is connected across an AC supply of 250 V, having variable frequency. The power dissipated at resonance condition is ________×102 W.
PhysicsAlternating CurrentJEE MainJEE Main 2021 (20 Jul Shift 2)
Solution:
2419 Upvotes Verified Answer
The correct answer is: 125

XL=XC (due to resonance)

Z=R so irms=VZ=VR

V2R=250×2505=125×102 W

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