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Question: Answered & Verified by Expert
A simple harmonic motion is represented by xt=sin2ωt-2cos2ωt. The angular frequency of oscillation is given by
PhysicsOscillationsNEET
Options:
  • A ω
  • B 2ω
  • C 4ω
  • D ω2
Solution:
1039 Upvotes Verified Answer
The correct answer is: 2ω
x=sin2ωt-2cos2ωt

=1-3cos2ωt

=1-31+cos2ωt2

= -12-32cos2ωt

Which is a periodic function with angular frequency of 2ω .

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