A simple pendulum consisting of a mass M attached to a string of length L is released from rest at an angle α . A pin is located at a distance l below the pivot point. When the pendulum swings down, the string hits the pin as shown in the figure. If the particle doesn't undergo a complete vertical circle, then the maximum angle θ π 2 through which the string swings after hitting the pin is

Question

A simple pendulum consisting of a mass M attached to a string of length L is released from rest at an angle α . A pin is located at a distance l below the pivot point. When the pendulum swings down, the string hits the pin as shown in the figure. If the particle doesn't undergo a complete vertical circle, then the maximum angle θ π 2 through which the string swings after hitting the pin is, cos - 1 ⁡ L cos ⁡ α + l L + l, cos - 1 ⁡ L cos ⁡ α - l L - l, cos - 1 ⁡ L cos ⁡ α + l L - l, cos - 1 ⁡ L cos ⁡ α - l L + l

MARKS App · Accepted Answer

At the bottom most point, square of speed of bob, v 2 = 2 g L 1 – c o s α It will rise further to a height, h = v 2 2 g = L 1 - cos ⁡ α or L - l 1 - cos ⁡ θ = L 1 - cos ⁡ α ∴ θ = cos - 1 ⁡ L cos ⁡ α - l L - l

Search any question & find its solution

Looking for more such questions to practice?