A slab of a glass of refractive index 1 . 5 and thickness 3 cm is placed with the faces perpendicular to the principal axes of a concave mirror. If the radius of curvature of the mirror is 10 cm , the distance at which an object must be placed from the mirror so that image coincides with the object is

Question

A slab of a glass of refractive index 1 . 5 and thickness 3 cm is placed with the faces perpendicular to the principal axes of a concave mirror. If the radius of curvature of the mirror is 10 cm , the distance at which an object must be placed from the mirror so that image coincides with the object is, 9 cm, 10 cm, 11 cm, 12 cm

MARKS App · Accepted Answer

μ = 1.5 = 3 / 2 Δ x = t 1 - 1 μ = 3 1 - 1 3 / 2 = 3 1 3 Δ x = 1 cm object distance = 10 + 1 = 11 cm

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