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Question: Answered & Verified by Expert
A small soap bubble of radius 4cm is trapped inside another bubble of radius 6cm without any contact. Let P2 be the pressure inside the inner bubble and P0, the pressure outside the outer bubble. Radius of another bubble with pressure difference P2-P0 between its inside and outside would be:
PhysicsMechanical Properties of FluidsJEE MainJEE Main 2018 (16 Apr Online)
Options:
  • A

    2.4 cm

  • B 12 cm
  • C 4.8 cm
  • D 6 cm
Solution:
2609 Upvotes Verified Answer
The correct answer is:

2.4 cm



P2P1=4Tr1....(1)P1P0=4Tr2  .....(2)adding (1)&(2)P2P0=4Tr1+4Tr2P2=P0+4Tr1+4Tr2P2=P0+4T6+4T4

for another bubble of radius r

P2= P0+4Tr

   1r=16+14

   r=2.4 cm

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